internal/sys/hsu: expose hsurc identifier
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Test / Create distribution (push) Successful in 33s
Test / Hakurei (push) Successful in 3m10s
Test / Hpkg (push) Successful in 4m5s
Test / Sandbox (race detector) (push) Successful in 4m35s
Test / Hakurei (race detector) (push) Successful in 5m17s
Test / Sandbox (push) Successful in 1m16s
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This maintains a compatible interface for now, to ease merging of the upcoming changes to internal/app. Signed-off-by: Ophestra <cat@gensokyo.uk>
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@ -24,7 +24,8 @@ type Hsu struct {
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var ErrHsuAccess = errors.New("current user is not in the hsurc file")
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func (h *Hsu) Uid(identity int) (int, error) {
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// ID returns the current user hsurc identifier. ErrHsuAccess is returned if the current user is not in hsurc.
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func (h *Hsu) ID() (int, error) {
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h.idOnce.Do(func() {
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h.id = -1
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hsuPath := internal.MustHsuPath()
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@ -54,11 +55,15 @@ func (h *Hsu) Uid(identity int) (int, error) {
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}
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})
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uid := -1
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if h.id >= 0 {
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uid = 1000000 + h.id*10000 + identity
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return h.id, h.idErr
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}
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return uid, h.idErr
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func (h *Hsu) Uid(identity int) (int, error) {
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id, err := h.ID()
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if err == nil {
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return 1000000 + id*10000 + identity, nil
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}
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return id, err
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}
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// MustUid calls [State.Uid] and terminates on error.
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