ldd: remove timeout

The program generally never blocks, and it is more flexible to leave it up to the caller to set a timeout.

Signed-off-by: Ophestra <cat@gensokyo.uk>

ldd/exec.go

@@ -7,7 +7,6 @@ import (
 	"io"
 	"os"
 	"os/exec"
-	"time"
 
 	"hakurei.app/check"
 	"hakurei.app/container"
@@ -27,9 +26,6 @@ const (
 
 	// lddName is the file name of ldd(1) passed to exec.LookPath.
 	lddName = "ldd"
-	// lddTimeout is the maximum duration ldd(1) is allowed to ran for before it
-	// is terminated.
-	lddTimeout = 15 * time.Second
 )
 
 // Resolve runs ldd(1) in a strict sandbox and connects its stdout to a [Decoder].
@@ -52,7 +48,7 @@ func Resolve(
 		}
 	}
 
-	c, cancel := context.WithTimeout(ctx, lddTimeout)
+	c, cancel := context.WithCancel(ctx)
 	defer cancel()
 
 	var toolPath *check.Absolute